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f(x)=8x-6-2x^2 for xlt=2=32 x-30-8x^2 ...

`f(x)=8x-6-2x^2` for `xlt=2=32 x-30-8x^2` for `x >2` tangents `[T_1:y=m_Hx+b_H] and T_2:y=m_2x+b_2]` have highest and lowest y intercepts in the first quadrant respectively on the function

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