The expression `x^2-4px+q^2> 0` for all real x and also `r^2+ p^2 < qr` the range of `f(x) = (x+r) / (x^2 +qx + p^2)` is

(i) If x^2-px+4 >0 for all real 'x' then find 'p' ?

If x^2-px+4gt0 for all real 'x' then find 'p'

Show that the roots of the equation x^(2)+px-q^(2)=0 are real for all real values of p and q.

(i) If x^(2)-px+4>0 for all real 'x' then find 'p'?

The quadratic expression (2X+1)^(2)-pX+q!=0 for any real X, if

Show that the expression (px^(2)+3x-4)/(p+3x-4x^(2)) will be capable of all values when x is real,provided that p has any value between 1 and 7.

If (alpha+sqrtbeta) and (alpha-sqrtbeta) are the roots of the equation x^2+px+q=0 where alpha,beta ,p and q are real, then the roots of the equation (p^2-4q)(p^2x^2+4px)-16q =0 are

If -4 is a root of the equation x^(2)+px-4=0 and if the equation x^(2)+px+q=0 are equal roots, find the values of p and q.