[" The potential energy of a "1Kg" particle free to move along "],[" the "X" -axis in a conservative field is given by "],[V(x)=((x^(4))/(4)-(x^(2))/(2))J],[" particle is "2J" .Then the maximum speed (in "ms^(-1)" ) is "]

The potential energy of a 1 kg particle free to move along the x- axis is given by V(x) = ((x^(4))/(4) - x^(2)/(2)) J The total mechainical energy of the particle is 2 J . Then , the maximum speed (in m//s) is

The potential energy of a 1 kg particle free to move along the x- axis is given by V(x) = ((x^(4))/(4) - x^(2)/(2)) J The total mechainical energy of the particle is 2 J . Then , the maximum speed (in m//s) is

The potential energy of a 1 kg particle free to move along the x- axis is given by V(x) = ((x^(4))/(4) - x^(2)/(2)) J The total mechainical energy of the particle is 2 J . Then , the maximum speed (in m//s) is

The potential energy of a 1kg particle free to move along the x-axis is given by V(x)=(x^(4)/4-x^(2)/2)J The total mechanical energy of the particle is 2J then the maximum speed (in m//s) is

The potential energy of a 2 kg particle free to move along the x- axis is given by V(x)[(x^(4))/(4)-(x^(2))/(2)]jou l e The total mechanical energy of the particle is 0.75 J . The maximum speed of the particle ( in m//s) is :

The PE of a 2 kg particle, free to move along x-axis is given by V(x)=((x^(3))/(3)-(x^(2))/(2))J. The total mechanical energy of the particle is 4 J. Maximum speed (in ms^(-1) ) is

The PE of a 2 kg particle, free to move along x-axis is given by V(x)=((x^(3))/(3)-(x^(2))/(2))J. The total mechanical energy of the particle is 4 J. Maximum speed (in ms^(-1) ) is

The PE of a 2 kg particle, free to move along x-axis is given by V(x)=((x^(3))/(3)-(x^(2))/(2))J. The total mechanical energy of the particle is 4 J. Maximum speed (in ms^(-1) ) is