[" 16."x-y+z=1],[" 2x+ "y-z=2],[x-2y-z=4]

2x+y+z=1x-y+2z=-1,3x+2y-z=4

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

2x+y-z=1 x-y+z=2 3x+y-2z=-1

2x-y+z=6,x+2y+3z=3,3x+y-z=4

Prove the identities: |[z, x, y],[ z^2,x^2,y^2],[z^4,x^4,y^4]|=|[x, y, z],[ x^2,y^2,z^2],[x^4,y^4,z^4]|=|[x^2,y^2,z^2],[x^4,y^4,z^4],[x, y, z]| =x y z (x-y)(y-z)(z-x)(x+y+z)

Prove the identities: |[z, x, y],[ z^2,x^2,y^2],[z^4,x^4,y^4]|=|[x, y, z],[ x^2,y^2,z^2],[x^4,y^4,z^4]|=|[x^2,y^2,z^2],[x^4,y^4,z^4],[x, y, z]| =x y z (x-y)(y-z)(z-x)(x+y+z)

Solve : 2x-y+z=4 , x+3y+2z=12 , 3x+2y+3z=16

The values of x, y, z for the equations x-y+z=1, 2x-y=1, 3x+3y-4z=2 are