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If (ax)/(cos theta) + (by)/sin theta = a...

If `(ax)/(cos theta) + (by)/sin theta = a^2 - b^2, ``(ax sin theta)/ (cos^2 theta) - (by cos theta)/(sin^2 theta) = 0`, `then (ax)^(2/3) + (by)^(2/3)=`

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`(ax)/costheta+(by)/sintheta = a^2-b^2->(1)`
`(axsintheta)/cos^2theta - (bycostheta)/sin^2theta = 0`
`=>(bycostheta)/sin^2theta = (axsintheta)/cos^2theta `
`=>by = (axsin^3theta)/cos^3theta`
Putting value of `by` in (1),
`(ax)/costheta+(axsin^2theta)/cos^3theta = a^2-b^2`
`=>ax(cos^2theta+sin^2theta) = (a^2-b^2)cos^3theta`
`=>ax = (a^2-b^2)cos^3theta`
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