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A sound wave of pressure amplitude 14 pa...

A sound wave of pressure amplitude 14 pascal propagates through the air medium. The normal pressure of air is `1.0xx10^(5)N//m^(2)` the difference between maximum and minimum pressure in the medium is

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The equation of a sound wave in air is given by rho = (0.01 N//m^(2)) [sin (1000 s^(-1)) t - (3.0 m^(-1))x] (a) Find the frequency, wavelength and the speed of sound wave in air. (b) If the equilibrium pressure of air is 1.0 xx 10^(5) N//m^(2) , what are the maximum and minimum pressure at a point as the wave passes through that point ?

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A sound wave of wavelength 20pi cm travels in air if the difference between the maximum and minimum pressures at a given point is 3.0xx10^-3 N//m^2 . Now sound level is increased by 20 dB, if the new amplitude of vibration of the particles of the medium at that given point is 20k (in Å ) then 'k' is : (The bulk modulus of air is 1.5xx10^5 N//m^2 ) (wavelength is same in both cases )

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