If the general solution of `sin5x=cos2x` is of the form `a_n.pi/2` for `n=0,+-1,+-2,....` then `a_n=`

If the general solution of sin 5x = cos 2x is of the form a_(n),(pi)/(2)" or "n=0, pm 1, pm2,....," then "a_(n)=

If solution of the equation sin^(4)2x+cos^(4)2x=sin2x*cos2x is of the form (n pi)/(2)+(pi)/(k),n in I, then value of k is

A : The general solution of sin x = -1 is n pi + (-1)^(n)(3pi)/(2), n in Z R : The principal solution of sin x = 0 lies in [-pi//2, pi//2]

The general solution of the trigonometric equation sin x+cos x=1 is given by x=2n pi,n0,+-1,+-2x=2n pi+(pi)/(2);n=0,+-1,+-2,...x=n pi+(-1)^(n)(pi)/(4)-(pi)/(4)n=0,+-1,+-2none of these

The general solution of the equation : sum_(r =1)^n cos(r^2 x) sin(r x) = 1/2 is

Which of the following is not the general solution of 2^(cos2x)+1=3. 2^-sin^(2x)? (a)npi,n in Z (b) (n+1/2)pi,n in Z (n-1/2)pi,n in Z (d) none of these

The general solution of cos x cos6x=-1 is x=(2n+1)pi,n in Zx=2n pi,quad n in Zx=n pi,n in Z(d) none of these

Which of the following is not the general solution of 2^(cos2x)+1=3. 2^(-sin^2 x)? (a) npi,n in Z (b) (n+1/2)pi,n in Z (c) (n-1/2)pi,n in Z (d) none of these

Which of the following is not the general solution of 2^(cos2x)+1=3. 2^(-sin^2 x)? (a) npi,n in Z (b) (n+1/2)pi,n in Z (c) (n-1/2)pi,n in Z (d) none of these

Which of the following is not the general solution of 2^(cos2x)+1=3. 2^-sin^(2x)? (a) npi,n in Z (b) (n+1/2)pi,n in Z (n-1/2)pi,n in Z (d) none of these