The equation of straight line equally inclined to the axes and equidistant from the point `(1, -2)` and `(3,4)` is:

If line y-x-1+2=0 is equally inclined to axes and equidistant from the points (1,-2) and (3,4), then lambda dis

If line y-x-1+lambda=0 is equally inclined to axes and equidistant from the point (1,-2) and (3,4) ,the lambda is

If line y - x - 1 +λ= 0 is equally inclined to axes and equidistant from the points (1, - 2) and (3, 4) , then lambda is

The equation of the line through (3,1,2) and equally inclined to the axes is

The number of straight lines which are equally inclined to both the axes is

The equation of straight line which is equidistant from the points A(2,-2),B(6,1) and C(-3,4) can be

Derive the equation of the locur of a point equidistant from the points (1, -2, 3) and (-3,4,2).

Find the equation of the straight line which makes equal intercepts on the axes and passes through the point (1,-3).