Area bounded by the curve `f(x) = cos x` which is bounded by the lines `x =0` and `x=pi` is

Area under the curve y = x sin x^(2) , bounded by the lines x = 0 and x= sqrt(pi//2) is

The area (in square unit) bounded by the curve y= sec x, the x-axis and the lines x=0 and x=(pi)/(4) is-

Find the area of the region bounded by the curve y=cos x , x axis and the ordinates x=0 and x=2pi

Find the area bounded by the curve y = cos x + 1 and the lines x = 0 and x = a. Hence find the greatest area

Find the area of the region bounded between the curves y = sinx and y = cos x and the lines x = 0 and x = pi .

The area bounded by the curve y=abs(x) , X axis and the lines x=-pi " and " x=pi is

The area bounded by the curve y=abs(x) , X axis and the lines x=-pi " and " x=pi is

Calculate the area bounded by the curve: f(x)=sin^2(x/2) , axis of x and the ordinates: x=0, x=pi/2 .

Let f (x) be a continous function such that the area bounded by the curve y =f (x) x-axis and the lines x=0 and x =a is (a ^(2))/( 2) + (a)/(2) sin a+ pi/2 cos a, then f ((pi)/(2)) is