For a saturated solution of `AgCl` at `25^(@)C,k=3.4xx10^(-6)ohm^(-1)cm^(-1)` and that of `H_(2)O(l)` used is `2.02xx10^(-6)ohm^(-1)cm^(-1). lambda_(m)^(@)` for `AgCl` is `138ohm^(-1)cm^(2)mol^(-1)` then the solubility of AgCl in moles per liter will be

For a saturated solution of AgCl at 25^(@)C,k=3.4xx10^(-6) ohm^(-1)cm^(-1) and that of H_(2)O (l) used is 2.02xx10^(-6) ohm^(-1) cm^(-1),lambda_(m)^(@) for AgCl is 138 ohm^(-1) cm^(2) "mol"^(-1) then the solubility of AgCl in "mole"s per litre will be:

For a saturated solution of AgCl at 25^(@)C,k=3.4xx10^(-6) ohm^(-1)cm^(-1) and that of H_(2)O (l) used is 2.02xx10^(-6) ohm^(-1) cm^(-1),lambda_(m)^(@) for AgCl is 138 ohm^(-1) cm^(2) "mol"^(-1) then the solubility of AgCl in "mole"s per litre will be:

For a saturated solution of AgCl at 25^(@)C , specific conductance is 3.41xx10^(-6)ohm^(-1) cm^(-1) and that of water used for preparing the solution is 1.60xx10^(-6)ohm^(-1)cm^(-1) . If lamda_(AgCl)^(oo)=138.3ohm^(-1)cm^(2)eq^(-1) , the K_(sp) of AgCl is 0.17xx10^(-x)M^(2) . The value of x is :

The conductivity of saturated solution of AgCl is found to be 1.86 xx 10^(-6) ohm^(-1)cm^(-1) and that of water is 6xx 10^(-8) ohm^(-1)cm^(-1) . If lamda^0 AgCl is

At 298 K, the conductivity of a saturated solutioni of Agcl in water is 2.6xx10^(-6)ohm^(-1)cm^(-1) givem lamda_(m)^(oo)(Ag^(+))=63ohm^(-1)cm^(2)mol^(-1) and lamda_(m)^(oo)(Cl^(-))=67ohm^(-1)cm^(2)mol^(-1) The solubility product of AgCl is

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

The specific conductance of a saturated solution of AgCl at 25^(@) C is 2.28 xx 10^(-6) S cm^(-1) . If solubility of AgCl " is " 2.35 xx 10^(-x) gL^(-1) ( lambda_(AgCl)^(@) = 138.3 S cm^(2) mol^(-1)) then x is