Determine the elongation of the steel bar `1m` long and `1.5 cm^(2)` cross-sectional area when subjected to a pull of `1.5xx10^(4) N.`
`(Take Y=2.0xx10^(11 )N//m^(2))`.

The magnitude of force developed by raising temperature from 0^(@) to 100^(@)C of an iron bar 1.00 m long and 1cm^(2) cross-sectional area (alpha=10^(-5)//.^(@)C and Y=10^(11)N//m^(2))

A brass of length 2 m and cross-sectional area 2.0 cm^(2) is attached end to end to a steel rod of length and cross-sectional area 1.0 cm^(2) . The compound rod is subjected to equal and oppsite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, the length of the steel rod (L) is { Y_(Brass) = 1.0 xx 10^(11) N//m^(2) and Y_(steel) = 2.0 xx 10^(11) N//m^(2)

A brass of length 2 m and cross-sectional area 2.0 cm^(2) is attached end to end to a steel rod of length and cross-sectional area 1.0 cm^(2) . The compound rod is subjected to equal and oppsite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, the length of the steel rod (L) is { Y_(Brass) = 1.0 xx 10^(11) N//m^(2) and Y_(steel) = 2.0 xx 10^(11) N//m^(2)

Find the total elongation of the bar, if the bar is subjected to axical froces as shown in figure . The cross-section area of bar is 10 cm^(2) . [Take E = 8 xx 10 ^(2) "dyne"//cm^(2)]

A steel rod of cross-sectional area 1m^(2) is acted upon by forces shown in the fig. Determine the total elongation of the bar. Take Y=2.0xx10^(11)N//m^(2) .

A brass rod of length 2 m and corss-sectinal area 2.0 cm^(2) is attached to end to a steel rod of length L and corss-sectinal area 1.0 cm^(2) . The compound rod is subjected to equal and opposite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, then the length of the steel rod L is (Y_("brass") = 1.0 xx 10^(11) Nm^(-2) and y_("steel") = 2.0 xx 10^(11) Nm^(-2))

A steel rod of cross-sectional area 1m^(2) is acted upon by forces as shown in the Fig. Determine the total elongation of the bar. Take Y = 2.0xx10^(11) N//m^(2)

What is the force requiredto stretch a steel wire of 1 cm^(2) cross-section to 1.1 times its length ? (Y = 2 xx 10^(11) N//m^(2))

A copper rod with length 1.4 m and area of cross-section of 2 cm^2 is fastened to a steel rod with length L and cross-sectional area 1 cm^2 . The compound rod is subjected to equal and opposite pulls to magnitude 6.00xx10^4 N at its ends . (a) Find the length L of the steel rod if the elongation of the two rods are equal . (b) What is stress in each rod ? (c ) What is the strain in each rod ? [Y_"steel"=2xx10^11 Pa , Y_(Cu)=1.1xx10^11 Pa]