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(sqrt(5)-2)(sqrt(3)-sqrt(5))...

(sqrt(5)-2)(sqrt(3)-sqrt(5))

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Simplify: (2sqrt(3)+sqrt(5))(2sqrt(3)-sqrt(5))

Check whether (2sqrt(3)+sqrt(5))*(2sqrt(3)-sqrt(5)) is rational or irrotational? Justify your answer

rationalize the denominators (a) (1)/(sqrt(2sqrt(7)+sqrt(5))) (b) (2sqrt(5))/(sqrt(3)+sqrt(5))

sqrt(10+2sqrt(6)+2sqrt(10)+2sqrt(15)) is equal to (sqrt(2)+sqrt(3)+sqrt(5))(sqrt(2)+sqrt(3)-sqrt(5))(c)(sqrt(2)+sqrt(5)-sqrt(3))(d) None of these

1/(sqrt(2)+sqrt(3)+sqrt(5))+1/(sqrt(2)+sqrt(3)-sqrt(5))

(1)/(sqrt(2)+sqrt(3)-sqrt(5))+(1)/(sqrt(2)-sqrt(3)-sqrt(5))

[(1)/(sqrt(2)+sqrt(3)-sqrt(5))+(1)/(sqrt(2)-sqrt(3)-sqrt(5))] in simplified form equals (a) 0 (b) (1)/(sqrt(2)) (c) 1 (c) sqrt(2)

4 sin 27^(0)= 1) sqrt(5+sqrt(5))+sqrt(3-sqrt(5)) 2) sqrt(5-sqrt(5))+sqrt(3+sqrt(5) 3) sqrt(5+sqrt(5))-sqrt(3-sqrt(5)) 4) sqrt(5+sqrt(5))+sqrt(3+sqrt(5)

Simplify (i) (3-sqrt(11))(3+sqrt(11)) (ii) (-3+ sqrt(5))(-3-sqrt(3)-sqrt(5)) (iii) (3- sqrt(3))^(2) (iv) (sqrt(5) - sqrt(3))^(2) (v) (5+ sqrt(7))(2+ sqrt(5)) (vi) (sqrt(5) - sqrt(2))(sqrt(2) - sqrt(3))