A magnetised steel wire `31.4cm` long has a pole strength of `0*2Am`. It is bent in the form of a semicircle. Calcualte its magnetic moment.

A magnetised steel wire 31.4 cm long has a pole strength of 0.2 Am. It is then bent in the form of semicircle. Calculate the new magnetic moment.

A magnetised steel wire of length 32.8 cm has pole -strength 1A.m If the wire is bent in the form of a semicircle , what will be its magnetic moment ?

A straight steel wire of length l has a magnetic moment M. When it is bent in the form of a semi - circle its magnetic moment will be

A magnetic wire of dipole moment 4pi Am^(2) is bent in the form of semicircle. The new magnetic moment is

A magnetic wire of dipole moment 4pi Am^(2) is bent in the form of semicircle. The new magnetic moment is

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be

A straight steel wire of length l has magnetic moment m. If the wire is bent in the form of a semicircle the new value of the magnetic dipole moment is ......... .