The dimensions of coefficient of thermal conductivity is

Options

A. `ML^(2) T^(-1) K^(-1)`
B. `MLT^(-3) K^(-1)`
C. `MLT^(-2) K^(-1)`
D. `MLT^(-3) K`

Answer

B

Explanation

(2) `(Delta Q)/(Delta t) = (K (theta_(2) - theta_(1)) A)/(L), K :` thermal conductivity
`K = (Delta Q)/(Delta t) (L)/((theta_(2) - theta_(2)) A)`
Unit : `(j o u l e . M)/(s. k e l vi n . M^(2)) = (j o u l e)/(s. k e l vi n. m)`
`[K] = (ML^(2) T^(-2))/(T. K.L) = [MLT^(-3) k^(-1)]`