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The dimensions of coefficient of thermal...

The dimensions of coefficient of thermal conductivity is

A

`ML^(2) T^(-1) K^(-1)`

B

`MLT^(-3) K^(-1)`

C

`MLT^(-2) K^(-1)`

D

`MLT^(-3) K`

Text Solution

Verified by Experts

The correct Answer is:
B
(2) `(Delta Q)/(Delta t) = (K (theta_(2) - theta_(1)) A)/(L), K :` thermal conductivity
`K = (Delta Q)/(Delta t) (L)/((theta_(2) - theta_(2)) A)`
Unit : `(j o u l e . M)/(s. k e l vi n . M^(2)) = (j o u l e)/(s. k e l vi n. m)`
`[K] = (ML^(2) T^(-2))/(T. K.L) = [MLT^(-3) k^(-1)]`
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  • Three metal rods of coefficient of thermal conductivities K,2K,3K conducts heats of 3Q, 2Q,Q per seconds through unit area then the ratio of temperature gradients .

    A
    `9:3:1`
    B
    `9:1:1`
    C
    `3:1:1`
    D
    `1:1:1`

  • The unit of thermal conductivity is :

    A
    `JmK^(-1)`
    B
    `Jm^(-1)K^(-1)`
    C
    `WmK^(-1)`
    D
    `Wm^(-1)K^(-1)`

  • The unit of thermal conductivity is :

    A
    `W m^(-1) K^(-1)`
    B
    `J m^(-1) K^(-1)`
    C
    `J m^(-1) K^(-1)`
    D
    `W m K^(-1)`

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