The dimensions of permittivity `epsilon_(0)` are

Options

A. `ML^(3) T^(-4) A^(2)`
B. `M^(-1) L^(-3) T^(4) A^(2)`
C. `ML^(3) T^(-4) A^(2)`
D. `ML^(-3) T^(-4) A^(2)`

Answer

B

Explanation

(2) `F = (1)/(4 pi epsilon_(0)) (q_(1) q_(2))/(r^(1)) implies epsilon_(0) = (q_(1) q_(2))/(4 pi F r^(2))`
Unit of `epsilon_(0) : ((c o u l)^(2))/(N m^(2)) = ([AT]^(2))/([MLT^(-2)] [L]^(2))` ltbgt `[epsilon_(0)] = M^(-1) L^(-3) T^(4) A^(2)`