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A student measures that distance travers...

A student measures that distance traversed in free fall of a body, initially at rest in given time. He uses this data to estimated `g`, the acceleration due to gravity. If the maximum percentage error in measurement of the distance and the time are `e_(1)` and `e_(2)`, respectively, the percentage error in the estimation of `g` is

A

`e_(2) - e_(1)`

B

`e_(1) + 2e_(2)`

C

`e_(1) + e_(2)`

D

`e_(1) - 2e_(2)`

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To solve the problem of estimating the percentage error in the acceleration due to gravity \( g \) based on the measurements of distance and time, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: The distance \( h \) traversed by a body in free fall from rest is given by the equation: \[ h = \frac{1}{2} g t^2 \] From this equation, we can express \( g \) as: \[ g = \frac{2h}{t^2} \] 2. **Identifying Errors**: Let \( e_1 \) be the maximum percentage error in the measurement of distance \( h \), and \( e_2 \) be the maximum percentage error in the measurement of time \( t \). 3. **Calculating Percentage Error in \( g \)**: To find the percentage error in \( g \), we need to differentiate the equation for \( g \): \[ g = \frac{2h}{t^2} \] Using the rules of differentiation for products and quotients, we can find the relative error in \( g \): \[ \frac{\Delta g}{g} = \frac{\Delta h}{h} + 2 \frac{\Delta t}{t} \] Here, \( \Delta h \) and \( \Delta t \) represent the absolute errors in \( h \) and \( t \) respectively. 4. **Expressing in Terms of Percentage Errors**: The percentage errors can be expressed as: \[ \frac{\Delta h}{h} = \frac{e_1}{100} \quad \text{and} \quad \frac{\Delta t}{t} = \frac{e_2}{100} \] Substituting these into the equation gives: \[ \frac{\Delta g}{g} = \frac{e_1}{100} + 2 \cdot \frac{e_2}{100} \] 5. **Final Expression for Percentage Error in \( g \)**: Multiplying the entire equation by 100 to convert to percentage gives: \[ \text{Percentage error in } g = e_1 + 2e_2 \] ### Conclusion: Thus, the percentage error in the estimation of \( g \) is given by: \[ \text{Percentage error in } g = e_1 + 2e_2 \]

To solve the problem of estimating the percentage error in the acceleration due to gravity \( g \) based on the measurements of distance and time, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: The distance \( h \) traversed by a body in free fall from rest is given by the equation: \[ h = \frac{1}{2} g t^2 ...
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