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A particle is given velocity 3 m//s alon...

A particle is given velocity `3 m//s` along the positive x-axis subjected to constant accelaration `4 m//s^(2)` along the positive y-axis. Find the distaplacement of the particle in `2 s` and trajectory followed by the particle.

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To solve the problem step by step, we will calculate the displacement of the particle after 2 seconds and determine the trajectory it follows. ### Step 1: Identify the initial conditions - Initial velocity along the x-axis, \( u_x = 3 \, \text{m/s} \) - Initial velocity along the y-axis, \( u_y = 0 \, \text{m/s} \) (since there is no initial velocity in the y-direction) - Acceleration along the y-axis, \( a_y = 4 \, \text{m/s}^2 \) - Time, \( t = 2 \, \text{s} \) ...
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Knowledge Check

  • Three particles starts from origin at the same time with a velocity 2 ms^-1 along positive x-axis, the second with a velocity 6 ms^-1 along negative y-axis, Find the velocity of the third particle along x = y line so that the three particles may always lie in a straight line.

    A
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    B
    `3 sqrt(2)`
    C
    `- 3 sqrt(2)`
    D
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    A
    `0^(@)`
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    C
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  • Three particles start from origin at the same time: one with velocity v^(1) along positive x-axis, the second along the positive y-axis with a velocity v^(2) and the third along the line y = x with such a speed that all the three always stay in a straight line, then velocity of the third particles is:

    A
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    B
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    C
    `(v_(1)v_(2))/(sqrt(v_(1)^(2)+v_(2)^(2)))`
    D
    `(v_(1)v_(2)sqrt2)/(v_(1)+v_(2))`
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