An object is projected so that its horizontal range `R` is maximum. If the maximum height of projectile is `H`, find the value of `H//R`.

Explanation

To solve the problem, we need to find the ratio \( \frac{H}{R} \) where \( H \) is the maximum height of the projectile and \( R \) is the maximum horizontal range.

### Step-by-Step Solution:

1. **Understanding the Range Formula**:
The formula for the horizontal range \( R \) of a projectile is given by:
\[
R = \frac{u^2 \sin 2\theta}{g}
...