Home
Class 11
PHYSICS
If an object is thrown at an angle of 60...

If an object is thrown at an angle of `60^(@)` with horizontal, find elevation angle of the object at its highest point as seen from the point of projection.

Text Solution

AI Generated Solution

To solve the problem of finding the elevation angle of an object at its highest point as seen from the point of projection, we can follow these steps: ### Step 1: Understand the problem The object is thrown at an angle of \(60^\circ\) with the horizontal. We need to find the angle of elevation (\(\beta\)) of the object when it reaches its maximum height as viewed from the point of projection. ### Step 2: Identify key points - Let the initial angle of projection be \(\theta = 60^\circ\). - The maximum height reached by the object will be denoted as \(H_{\text{max}}\). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION IN A PLANE

    CP SINGH|Exercise Exercises|69 Videos
  • LAWS OF THERMODYNAMICS

    CP SINGH|Exercise EXERCISE|131 Videos
  • MOTION IN A STRAIGHT LINE

    CP SINGH|Exercise EXERCISES|128 Videos

Similar Questions

Explore conceptually related problems

If a particle of mass m is thrown with speed at an angle 60° with horizontal, then angular momentum of particle at highest point about point of projection is

If a particle of mass m is thrown with speed v, at an angle 60° with horizontal, then angular momentum of particle at highest point about point of projection.

Knowledge Check

  • A projectile is fired at an angle of 45^(@) with the horizontal. Elevation angle of the projection at its highest point as seen from the point of projection is

    A
    `60^(@)`
    B
    `tan^(-1)(1/2)`
    C
    `tan^(-1)(sqrt(3)/2)`
    D
    `45^(@)`
  • A stone is thrown at an angle of 45^(@) to the horizontal with kinetic energy K. The kinetic energy at the highest point is

    A
    `(K)/(2)`
    B
    `(K)/(sqrt2)`
    C
    K
    D
    zero
  • A projectile is fired from level ground at an angle theta above the horizontal. The elevation angle phi of the highest point as seen from the launch point is related to theta by the relation.

    A
    `tan phi = 2 tan theta`
    B
    `tan phi = tan theta`
    C
    `tan phi = (1)/(2) tan theta`
    D
    `tan phi = (1)/(4) tan theta`
  • Similar Questions

    Explore conceptually related problems

    A body is projected at angle of 45^(@) to the horizontal . What is its velocity at the highest point ?

    projectile is fired from ground at an angle theta with horizontal. The elevation angle phi of heighest point as seen from launch point is related by the relation-

    A particle is projected at an angle theta with the horizontal . If angle of elevation of highest point of trajectory is phi when seen from point of projection, then

    A ball is projected with 20sqrt2 m//s at angle 45^(@) with horizontal.The angular velocity of the particle at highest point of its journey about point of projection is

    A body is projected at an angle of 30^(@) with the horizontal with momentum P .At its highest point the magnitude of the momentum is: