A ball is thrown such that the time of flight is `5 s` and the horizontal range is `200 m`. Find the magnitude and direction of velocity of projection.

Explanation

`T = (2 u sin theta)/(g) rArr 5 = (2)/(10) u sin theta rArr u sun theta = 25`
`R = u cos theta T rArr 200 = u cos theta xx 5 rArr u cos theta = 40`
`u = sqrt((u sin theta)^(2) + (u cos theta)^(2)) = sqrt((25)^(2) + (40)^(2)) m//s`
`= sqrt(2225) = 5sqrt(89) m//s`
`tan theta = (u sin theta)/(u cos theta) = (25)/(40) rArr theta = tan^(-1) ((5)/(8))`