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A ball is thrown with speed u at an angl...

A ball is thrown with speed `u` at an angle `theta` with horizontally. After how much time it will move perpendicular to the initial direction of motion.

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To solve the problem of determining the time after which a ball thrown with speed `u` at an angle `theta` with the horizontal moves perpendicular to its initial direction of motion, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Initial Conditions**: - The ball is thrown with an initial speed `u` at an angle `theta` with respect to the horizontal. - The initial velocity can be broken down into its horizontal and vertical components: - Horizontal component: \( u_x = u \cos(\theta) \) ...
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Knowledge Check

  • A particle is thrown with a speed u at an angle theta with horizontal. After how much time the velocity of particle will be perpendicular to the initial motion of direction

    A
    `(u)/(g cos theta)`
    B
    `(u)/(g sin theta)`
    C
    `(u sin theta)/(g)`
    D
    `(u cos theta)/(g)`
  • A ball is thrown with velocity 8 ms^(-1) making an angle 60^(@) with the horizontal.Its velocity will be perpendicular to the direction of initial velocity of projection after a time of

    A
    `1.6/sqrt3s`
    B
    `4/sqrt3s`
    C
    `0.6 s`
    D
    `1.6sqrt3 s`
  • A particle is projected with a speed u at an angle theta with the horizontal. What will be the speed of the particle when direction of motion of particle is at an angle alpha with the horizontal?

    A
    `u cos theta sec alpha`
    B
    `u sec theta cos alpha`
    C
    `u cos theta tan alpha`
    D
    `u cos theta cot alpha`
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