A particle moving with a velocity equal to `0.4 m//s` is subjected to an acceleration of `0.15 m//s^(2)` for `2 s`. in a direction at the right angle to its direction of motion. The resultant velocity is

Options

A. `0.7 m//s`
B. `0.5 m//s`
C. `0.1 m//s`
D. Between `0.7` and `0.1 m//s`

Answer

B

Explanation

`x: v_(x) = u_(x) = 0.4 m//s`
`y: v_(y) = a_(y) t = 0.15 xx 2 = 0.3 m//s`
`v = sqrt(v_(x)^(2) + v_(y)^(2)) = 0.5 m//s`