A projectile is projected with a kinetic energy `K`. If it has the maximum possible horizontal range, then its kinetic energy at the highest point will be

Options

A. `K//4`
B. `K//2`
C. `3K//4`
D. `K`

Answer

B

Explanation

`K = (1)/(2)m u^(2), theta = 45^(@)`
`K_(h) = (1)/(2) m(u cos 45^(@))^(2) = (1)/(2) m u^(2).(1)/(2) = (K)/(2)`