A projectile is thrown at an angle of `40^(@)` with the horizontal and its range is `R_(1)`. Another projectile is thrown at an angle of `40^(@)` with the vertical and its range is `R_(2)`. What is the relation between `R_(1)` and `R_(2)` ? (projection speed is same in both cases)

Options

A. `R_= R_(2)`
B. `R_(1) = 2 R_(2)`
C. `2 R_(1) = R_(2)`
D. `R_(1) = 0.8 R_(2)`

Answer

A

Explanation

Range is same for angles `theta` and `(90^(@) - theta)` for the given velocity.