A projectile is thrown into air so as to have the maximum possible range equal to `200`. Taking projection point as origin, the coordinates of the point where the velocity of the projectile is minimum, are

Options

A. `(200, 50)`
B. `(100, 50)`
C. `(100, 50)`
D. `(100, 100)`

Answer

B

Explanation

`R_(max) = (u^(2))/(g) = 200 m`
`H_(max) = (u^(2) sin^(2) 45^(@))/(2 g) = (u^(2))/(4g) = 50 m`

At the highest point `H`, the velocity is minimum.
Coordinates of `H -= ((R )/(2), H_(max))`
`-= (100, 50)`