Two projectiles, one fired from from surface of earth with velocity `10 m//s` and other fired from the surface of another planet with initial speed `5 m//s` trace idential trajectories. The value of acceleration due to the gravity on the planet is

Options

A. `2.5 m//s^(2)`
B. `3.6 m//s^(2)`
C. `4.9 m//s^(2)`
D. `6.4 m//s^(2)`

Answer

A

Explanation

`H_(1) = H_(2)`
`((10)^(2)sin^(2) theta)/(2 g_(1)) = ((5)^(2) sin^(2) theta)/(2 g_(2))`
`(g_(2))/(g_(1)) = (1)/(4) rArr g_(2) = (g_(1))/(4) rArr g_(2) = (g_(1))/(4) = (10)/(4) = 2.5 m//s^(2)`