A bomber plane moves horizontally with a speed of `600 m//s` and a bomb released from it, strikes the ground in `10 s`. The angle with horizontally at which it strikes the ground will be

Options

A. `tan^(-1) (1//2)`
B. `tan^(-1) (1//6)`
C. `tan^(-1) (4//5)`
D. `tan^(-1) (3//4)`

Answer

B

Explanation

`x: v_(x) = u = 600`
`y: v_(y) = g t = 10 xx 10 = 100`
`tan alpha = (v_(y))/(v_(x)) = (100)/(600) = (1)/(6)`
`alpha = tan^(-1)(1//6)`