A ball is thrown from a point with a speed 'v^(0)' at an elevation angle of `theta` . From the same point and at the same instant , a person starts running with a constant speed `('v_(0)')/(2) ` to catch the ball . Will the person be able to catch the ball ? If yes, what should be the angle of projection `theta` ?

Options

A. Yes, `60^(@)`
B. Yes, `30^(@)`
C. No
D. Yes, `45^(@)`

Answer

A

Explanation

Ball: `x = v_(0) cos theta t`
Man : `x'=(v_(0))/(2) t`
`x=x'`
`v_(0) cos theta = (v_(0))/(2)`
The horizontal component of velocity of the projection should be equal to the velocity of man
`v_(0) cos theta = (v_(0))/(2) rArr theta = 60^(@)`