a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

Options

A. `5.9`
B. `16.3`
C. `110.8`
D. `3.5`

Answer

D

Explanation

`R = (u_(1)^(2))/(g_(1)) sin 2theta = (u_(2)^(2))/(g_(2))sin 2theta`
`g_(2) = ((u_(2))/(u_(1)))^(2) g_(1) = ((3)/(5))^(2) xx 9.8 = 3.5 m//s^(2)`