Two thin uniform rings made of same material and of radii `R` and `4 R` are joined as shown. The mass of smaller ring is `m`. Find the `M.I.` about an axis passing through the center of mass of system of rings and perpendicular to the plane.

Explanation

To find the moment of inertia (M.I.) about an axis passing through the center of mass of the system of two rings, we will follow these steps:

### Step 1: Determine the Mass of Each Ring
- The mass of the smaller ring (radius R) is given as \( m \).
- The mass of the larger ring (radius \( 4R \)) can be found using the relationship of mass and radius since both rings are made of the same material. The mass of the larger ring is proportional to its circumference:
\[ \text{Mass of larger ring} = \frac{4R}{R} \cdot m = 4m \]
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