A particle A moves along a circle of radius `R=50cm` so that its radius vector r relative to the point O(figure) rotates with the constant angular velocity `omega=0.40rad//s`. Find the modulus of the velocity of the particle, and the modulus and direction of its total acceleration.

Explanation

Angular velocity of `A` about the center of circle

`omega_(A)=2omega`
`v_(A)=omega_(A) R=2 omega R=2xx0.4xx0.5=0.4 m//s`
`a_(A)=omega_(A)^(2) R=4omega^(2)R=4xx(0.4)^(2)xx0.5=0.32 m//s^(2)`