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The angular position of a swinging door is described by `theta=5+10t+20t^(2)`. Determine the angular position, angular speed and angular acceleration at `t=2 s`.

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`theta=5+10t+20t^(2)`
`omega=(d theta)/(dt)=10+40t`
` alpha=(domega)/(dt)=40`
At `t=2 s`,
`theta=5+10(2)+20(2)^(2)=5+20+80=105 rad`
`omega = 10+40(2)= 90 rad//s`
`alpha=40 rad//s^(2)`
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