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A solid body rotates with deceleration a...

A solid body rotates with deceleration about a stationary axis with an angular deceleration `betapropsqrt(omega)`, where `omega` is its angular velocity. Find the mean angular velocity of the body averaged over the whole time of rotation if at the initial moment of time its angular velocity was equal to `omega_0`.

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Verified by Experts

`betapropsqrtomega implies beta=komega^(1//2)` (`k`: constant)
`(domega)/(dt)= -komega^(1//2)`
`int_(0)^(omega)omega^(-1//2)domega=-kint_(0)^(t)tdt`
`(|omega^(1//2)|_(omega_(0))^(omega))/(1//2)=-kt`
`sqrtomega-sqrtomega_(0)=(-kt)/(2)`
`omega=(sqrtomega_(0)-(kt)/(2))^(2)`
where `omega` is an angular velocity at time `t`.
The body will stop, when `omega=0`.
`sqrtomega_(0)-(kt)/(2)=0 implies t=(2sqrtomega_(0))/(k)`
Again `beta=k omega(1//2)`
` implies omega(domega)/(d theta)=-komega^(1//2)`
`int_(omega_(0))^(omega)omega^(1//2)domega=-kint_(o)^(theta) d theta implies (|omega^((3)/(2))|_(omega_(0))^(omega))/((3)/(2))=-ktheta`
`omega^(3//2)-omega_(0)^(3//2)=-(3)/(2)ktheta`
when body stops, `omega=0`
` implies theta= (2omega_(0)^(3//2))/(3k)`
Average angular velocity
`undersetomega(-)=(theta)/(t)=((2omega_(0)^(3//2))/(3k))/((2sqrtomega_(0))/(k))=(omega_(0))/(3)`
OR
`undersetomega(-)=(int_(0)^(t)omegadt)/(int_(0)^(t)dt)`
` = (int_(0)^(t)(sqrtomega_(0)-(kt)/(2))^(2)dt)/(t)=(|(sqrtomega_(0)-(kt)/(2))^(3)|_(0)^(t))/((-k)/(2)txx3)`
` =((sqrtomega_(0)-(k)/(2)(2sqrtomega_(0))/(k))^(3)-(sqrtomega_(0))^(3))/((-k)/(2)xx(2sqrtomega_(0))/(k)xx3)=(omega_(0))/(3)`
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