Consider the situation as shown in the figure. The moment of inertia of wheel is `2 kg m^(2)` and its radius is `0.25 m`. Find the angular acceleration of the wheel, assuming no slipping.

Explanation

For block: `10-T=2a` (`i`)
For pulley: `TR=I alpha` (`ii`)
`a=R alpha implies a=(alpha)/(4)` (`iii`)
`10-8a=2xx(alpha)/(4)=(alpha)/(2)`
` implies (17alpha)/(2)=10 implies alpha = (20)/(17) rad//s^(2)`