A uniform rod of mass `m` and length `L` is suspended through two vertical strings of equal lengths fixed at ends. A small object of mass `2m` is placed at distance `L//4` from the left end. Find the tensions in the two strings.

Explanation

since the rod is in equilibrium

`SigmaF_(y)=0implies T_(1)+T_(2)=2mg+mg` …..(i)
Taking torque about `A`
`Sigma tau_(A)=0impliesT_(2)xxL=2mgxx(L)/(4)+mgxx(L)/(2)`
`T_(2)=mg, T_(1)=2mg`