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Find the angular momentum of the earth ...

Find the angular momentum of the earth
(a) about the sun due to its orbital motion and
(b) about its axis due to its spinning motion.

Text Solution

Verified by Experts

(`a`)
`r`: distance between the sun and the earth
`M_(e)`: mass of the earth
`omega`: angular speed of the earth about the sun
`omega=(2pi)/(T)`, `T=365 days`
Orbital angular momentum is
`M_(e)vr=M_(e)(romega)r=M_(e)r^(2)omega`

`R_(e)`: radius of the earth
Moment of inertia of the earth about its axis
`I=(2)/(5)M_(e)R_(e)^(2)`
Angular velocity of the earth about its axis
`omega^(t)=(2pi)/(T')`, `T'=24h`
Spin angular momentum `=Iomega'=(2)/(5)M_(e)R_(e)^(2)omega`
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Knowledge Check

  • The value of angular momentum of the earth rotating about its own axis is

    A
    `7xx10^(33) kg m^(2)//s`
    B
    `7xx10^(33) kg m^(2)//s`
    C
    `0.7xx10^(33) kg m^(2)//s`
    D
    zero
  • The angular velcity of the earth due to its spain motion is :

    A
    `(pi)/(3600xx12) ""rad//s`
    B
    `(2pi)/(3600xx6)""Rad //s`
    C
    `(pi)/(1800xx6)""rad//s`
    D
    `(3pi)/(3600 xx12)""Rad //s`
  • The rotation of earth about its axis is

    A
    periodic motion
    B
    simple harmonic motion
    C
    periodic but not simple harmonic motion
    D
    non-periodic motion
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