Home
Class 11
PHYSICS
A stone of mass m tied to the end of a s...

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by `T = Ar^n` where A is a constant, r is the instantaneous radius of the circle and n=....

Text Solution

Verified by Experts

Angular momentum of store is constant.
`Iomega = constant =K`
`mr^(2)omega=Kimplies omega=(k)/(mr^(2))`
Tension provides necessary centripetal force
`T=momega^(2)r=m((k)/(mr^(2)))^(2)r=(K^(2))/(m)r^(-3)=Ar^(n)`
`n=-3`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    CP SINGH|Exercise Exercise|172 Videos
  • RELATIVE MOTION

    CP SINGH|Exercise EXERCISE|33 Videos
  • SIMPLE HARMONIC MOTION

    CP SINGH|Exercise Exercises|125 Videos

Similar Questions

Explore conceptually related problems

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^2 where A is a constant, r is the instantaneous radius fo the circle and n=....

A stone of mass m tied to the end of a string is whirled around in a horizontal circle (neglect force du eto grvaity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then the tension in the given by T = A r^(n) , where A is a constant and r is instantaneous radius of the circle. Show that n = - 3 .

A stone of mass m, tied to the end of a string, is. whirled around in a horizontal circle (neglect gravity). The length of the string is reduced gradually such that mvr = constant. Then, the tension in the string is given · by T = Ar '', where A is a constant and r is the instantaneous radius of the circle. Then, n is equal to:

A stone is tied to the end of a string of length 1 and whirled in a horizental circle. When the string breaks then stone

Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity 2 rad s^(-1) . The tension of the string is (in newton)

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniforn speed of 2m//s .Then tension in the string is

A stone of mass 250 gram , attached at the end of a string of length 1.25 m is whirled in a horizontal circle at a speed of 5 m/s . What is the tension in the string ?

A stone of mass 0.1 kg tied to one end of a string lm long is revolved in a horizontal circle at the rate of (10)/(pi)" rev/s" . Calculate the tension in the string.

A stone tied at the end of string is whirled in a circle. If the string break, the stone flies away tangentially . Why ?

CP SINGH-ROTATIONAL MOTION-Exercise
  1. A stone of mass m tied to the end of a string, is whirled around in a ...

    Text Solution

    |

  2. Three point masses, each of mass m, are placed at the corners of an eq...

    Text Solution

    |

  3. The moment of inertia of a disc of mass M and radius R about an axis. ...

    Text Solution

    |

  4. Let I(A) and I(B) be moments of inertia of a body about two axes A and...

    Text Solution

    |

  5. A closed cylindrica tube containing some water (not filling the entire...

    Text Solution

    |

  6. A uniform cylinder has radius R and length L. If the moment of inertia...

    Text Solution

    |

  7. A solid sphere of mass M, radius R and having moment of inertia about ...

    Text Solution

    |

  8. Two circular discs are of same thickness. The diameter of A is twice t...

    Text Solution

    |

  9. The moment of inertia of a circular disc of mass M and radius R about ...

    Text Solution

    |

  10. From a uniform wire, two circular loops are made (i) P of radius r and...

    Text Solution

    |

  11. The moment of inertia of a uniform rod about a perpendicular axis pass...

    Text Solution

    |

  12. The density of a rod AB increases linearly from A to B its midpoint is...

    Text Solution

    |

  13. The M.I. of a rod about an axis through its center and perpendicular t...

    Text Solution

    |

  14. The moment of inertia of a thin uniform rod of mass M and length L abo...

    Text Solution

    |

  15. Three rings, each of mass m and radius r, are so placed that they touc...

    Text Solution

    |

  16. Two rings A (2m,R) and B (m,R) are placed such that these are perpendi...

    Text Solution

    |

  17. If I(0) is the moment of inertia body about an axis passing through it...

    Text Solution

    |

  18. A rod of length L is made of a uniform length L//2 of mass M(1) and a ...

    Text Solution

    |

  19. Four spheres each of mass M and diameter 2r, are placed with their cen...

    Text Solution

    |

  20. The ratio of the radii of gyration of a circular disc about a tangenti...

    Text Solution

    |

  21. One quarter sector is cut from a uniform circular disc of radius R. Th...

    Text Solution

    |