The moment of inertia of a disc of mass `M` and radius `R` about an axis. Which is tangential to sircumference of disc and parallel to its diameter is.

Options

A. `(5Mr^(2))/(4)`
B. `(5Mr^(2))/(2)`
C. `(3Mr^(2))/(4)`
D. `(Mr^(2))/(2)`

Explanation

`I_(1-1)=(I_(c.m.))dia+Mr^(2)`
`=(1)/(4)Mr^(2)+Mr^(2)=(5)/(4)Mr^(2)`