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A uniform cylinder has radius R and leng...

A uniform cylinder has radius `R` and length `L`. If the moment of inertia of this cylinder about an axis passing through its centre and normal to its circular face is `(mR^(2))/2` is equal to moment of inertia of the same cylinder about an axis passing through its centre and normal to its length, then

A

`L=R`

B

`L=sqrt3R`

C

`L=(R )/(sqrt3)`

D

`L=sqrt((3)/(2))R`

Text Solution

Verified by Experts

The correct Answer is:
B

`(1)/(2)MR^(2)=M((L^(2))/(12)+(R^(2))/(4))implies (R^(2))/(4)=(L^(2))/(12)impliesL=sqrt3R`
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