Two rings `A` (`2m,R`) and `B` (`m,R`) are placed such that these are perpendicular but common center. The `M.I.` of the system about an axis passing through the common center and perpendicular to the plane of `B` is

Options

A. `(1)/(2)mR^(2)`
B. `mR^(2)`
C. `(3)/(2)mR^(2)`
D. `2mR^(2)`

Explanation

To find the moment of inertia of the system consisting of two rings A and B, we will follow these steps:

### Step 1: Identify the Mass and Radius of the Rings
- Ring A has a mass of \(2m\) and radius \(R\).
- Ring B has a mass of \(m\) and radius \(R\).

### Step 2: Determine the Axis of Rotation
- The axis of rotation is passing through the common center of both rings and is perpendicular to the plane of ring B.
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