Four thin rods of same mass `m` and same length `L` form a square as shown in the figure. `M.I.` of this system about an axis through center `O` and perpendicular to its plane is

Options

A. `(4mL^(2))/(3)`
B. `(mL^(2))/(3)`
C. `(mL^(2))/(6)`
D. `(4mL^(2))/(3)`

Explanation

`M.I.` of one rod about `O`
`I_(1)=(mL^(2))/(12)+m((L)/(2))^(2)=(ML^(2))/(3)`
`I_(0)=4I_(1)=(4mL^(2))/(3)`