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Consider a uniform square plate of of si...

Consider a uniform square plate of of side and mass `m`. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is -

A

`(1)/(12)ma^(2)`

B

`(7)/(12)ma^(2)`

C

`(2)/(3)ma^(2)`

D

`(5)/(6)ma^(2)`

Text Solution

Verified by Experts


`I_(x)=I_(y)=(ma^(2))/(12)`
`I_(z)=I_(x)+I_(y)=(ma^(2))/(6)` (`bot^(ar)` axes theorem)
`OA=(a)/(sqrt2)`
`M.I.` about an axis passing through `A` and `bot^(ar)` to the plane
`I_(A)=(I_(z))_(c.m.)+m(OA)^(2)` (parallel axes theorem)
`=(ma^(2))/(6)+m((a)/(sqrt2))^(2)`
`=ma^(2)((1)/(6)+(1)/(2))=(2)/(3)ma^(2)`
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