The angle turned by a body undergoing circular motion depends on time as `theta=theta_(0)+theta_(1) t+theta_(2)r^(2)`. Then the angular acceleration of the body is

Options

A. `theta_(1)`
B. `theta_(2)`
C. `2theta_(1)`
D. `2theta_(2)`

Explanation

`theta=theta_(0)+theta_(1) t+theta_(2) t^(2), omega=(d theta)/(dt)=theta_(1)+2theta_(2)t`
`alpha=(d omega)/(dt)=2theta_(2)`