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The instantaneous angular position of a ...

The instantaneous angular position of a point on a rotating wheel is given by the equation
`theta(t) = 2t^(3) - 6 t^(2)`
The torque on the wheel becomes zero at

A

`t=2 s`

B

`t=1 s`

C

`t=0.2 s`

D

`t=0.25 s`

Text Solution

Verified by Experts

`theta=2t^(3)-6t^(2)`
`omega=6t^(2)-12t`
`alpha=12t-12=0implies t = 1 s`
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