A string is wound round the rim of a mounted flywheel of mass `20 kg` and radius `20 cm`. A steady pull of `25 N` is applied on the cord. Neglecting friction and mass of the string, the angular acceleration of the wheel in `rad//s^(2)` is

Options

A. `50`
B. `25`
C. `12.5`
D. `6.25`

Explanation

To find the angular acceleration of the flywheel, we can follow these steps:

### Step 1: Identify the given values
- Mass of the flywheel, \( m = 20 \, \text{kg} \)
- Radius of the flywheel, \( r = 20 \, \text{cm} = 0.2 \, \text{m} \)
- Tension in the string, \( T = 25 \, \text{N} \)

### Step 2: Calculate the torque (\( \tau \))
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