A flywheel of moment of inertia `I` is rotating with uniform angular speed `omega`. If a torque `tau` retards the wheel, then the time in which the wheel comes to rest is

Options

A. `(Iomega)/(tau)`
B. `(2Iomega)/(tau)`
C. `(Iomega)/(2tau)`
D. `(Iomega)/(4tau)`

Explanation

To solve the problem step by step, we can follow these logical steps:

### Step 1: Understand the given information
We have a flywheel with:
- Moment of inertia \( I \)
- Initial angular speed \( \omega_0 \)
- A torque \( \tau \) that is acting in the opposite direction to the rotation, causing the flywheel to decelerate.

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