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The moment of inertia of a body about a ...

The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 J`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?

A

` 4 s`

B

` 2 s`

C

` 8 s`

D

` 10 s`

Text Solution

Verified by Experts

`K=(1)/(2)I omega^(2)implies 1500=(1)/(2)xx1.2xxomega^(2)`
`omega=50 rad//s=omega_(0)+alpha timplies 50=25timplies t=2 s`
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