A uniform horizontal meter scale of mass `m` is suspended by two vertical strings attached to its two ends. A block of mass `3m` is placed on the `60 cm` mark. The tensions in the two strings are in the ratio

Options

A. `17 : 19`
B. `19 : 21`
C. `17 : 23`
D. `19 : 23`

Explanation

`T_(1)+T_(2)=mg+3mg=4mg` (`i`)
`tau_(A)=0impliesmgxx50+3mgxx60=T_(2)xx100` (`ii`)
`T_(2)=2.3mg, T_(1)=1.7mg`
`(T_(1))/(T_(2))=(17)/(23)`