A particle of mass `5g` is moving with a uniform speed of `3sqrt2 cm//s` in the `x-y` plane along the line `y=x+4`. The magnitude of its angular momentum about the origin in `g cm^(2)//s` is

Options

A. zero
B. `30`
C. `3sqrt2`
D. `60`

Explanation

To find the magnitude of the angular momentum of a particle moving in the x-y plane, we can follow these steps:

### Step 1: Identify the parameters of the problem
- Mass of the particle, \( m = 5 \, \text{g} \)
- Speed of the particle, \( v = 3\sqrt{2} \, \text{cm/s} \)
- The line along which the particle moves is given by \( y = x + 4 \).

### Step 2: Determine the position vector \( \mathbf{R} \)
...