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A solid sphere is rotating about a diame...

A solid sphere is rotating about a diameter at an angular velocity `omega`. If it cools so that its radius reduces to `I//n` of its original value, its angular velocity becomes

A

`(omega)/(n)`

B

`(omega)/(n^(2))`

C

`omega n`

D

`n^(2) omega`

Text Solution

AI Generated Solution

To solve the problem, we need to apply the principle of conservation of angular momentum. Here's a step-by-step solution: ### Step 1: Understand the initial conditions We have a solid sphere with an initial radius \( r \) and an initial angular velocity \( \omega \). The moment of inertia \( I_1 \) of the solid sphere about its diameter is given by the formula: \[ I_1 = \frac{2}{5} m r^2 \] ...
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